![]() I can calculate the amount I need for the current page. If there are no more chunks just return without any products if(!$request->ajax())). Laravel Version: 5.2 PHP Version: PHP 5.6.8 Database Driver & Version: 5.6.24 MySQL Community Server Description: Laravel Pagination does not support display all record. Can I get all collections of all pages in the controller and then calculate the amount using the standard collection method I tried to use get() instead of pagination, but the request is taking too long, due to API. I would like to count the rows but when i do that i got the count column. When ajax is requesting for more products it will get the products from session and get the correct chunk of products base on the page number ajax requested. Laravels paginator is integrated with the query builder and Eloquent ORM and provides convenient, easy-to-use pagination of database records with zero configuration. I have a eloquent request with GroupBy and SelectRaw with joins table. We will use Laravel pagination Eloquent so that we can render. How to paginate through joined records on laravel 0. This will give you more flexibility to build a query that will obtain only the results you need from the database. Get all products, set the number of item for each chunk (like paginate) and store it into session (we store the chunks into session so when ajax request comes in it won't call $products = Product::inRandomOrder()->get() again), first chunk will be the first pagination Those results are distributed on various pages, and multiple records are contained by each page. Laravel eloquent: Only retrieve entries where relationship has entries (join). To sort results in the database query, you’ll need to use the orderBy () method, and provide the table field you want to use as criteria for ordering. Solution Ajax + chunk + session + lazyload + paginate + eloquent + blade
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